0=2x^2-96x+576

Solution for 0=2x^2-96x+576 equation:

0=2x^2-96x+576

We move all terms to the left:

0-(2x^2-96x+576)=0

We add all the numbers together, and all the variables

-(2x^2-96x+576)=0

We get rid of parentheses

-2x^2+96x-576=0

a = -2; b = 96; c = -576;
Δ = b2-4ac
Δ = 962-4·(-2)·(-576)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-48\sqrt{2}}{2*-2}=\frac{-96-48\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+48\sqrt{2}}{2*-2}=\frac{-96+48\sqrt{2}}{-4}
$